testtt TEST 可以证明,当大小为 \(2^k\) 的某块,其地址也与 \(2^k\) 对齐时,由它分割出来的两个 \(2^{k-1}\) 大小的伙伴块,地址都对齐到 \(2^{k-1}\)。 设某大小为 \(2^k(k>0)\) 的块,其地址为 \(addr_{fa}\) ,有 \(addr_{fa} \bmod 2^k = 0\)。由它分割出来的两个 \(2^{k-1}\) 大小的伙伴块,设地 2024-07-13 #os #test
Hello World Welcome to Hexo! This is your very first post. Check documentation for more info. If you get any problems when using Hexo, you can find the answer in troubleshooting or you can ask me on GitHub. Quick 2024-03-20